Question

A particle initially starts from rest, travels a distance Y in the first two seconds and a distance of X in next two seconds then,

• A. $X=2Y$
• B. $X+Y=4X$
• C. $X+Y=4Y$
• D. $X=3Y$

Answer 1

Answer: (C), (D)

The correct options are
C $X+Y=4Y$
D $X=3Y$

$u=0$

$t=2sy=\frac{4}{2}a=2a$

$t=4s(X+Y)=\frac{16a}{2}=8a$

$X+Y=4Y\left(or\right)X=3Y$