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Question

A particle initially starts from rest, travels a distance Y in the first two seconds and a distance of X in next two seconds then,

A
X=2Y
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B
X+Y=4X
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C
X+Y=4Y
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D
X=3Y
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Solution

The correct options are
C X+Y=4Y
D X=3Y
u=0
t=2sy=42a=2a
t=4s(X+Y)=16a2=8a
X+Y=4Y(or)X=3Y

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