Question

A particle is acted upon by a force whose component's variations with time are shown in diagrams. Then the magnitude of change in momentum of the particle in 0.1 sec will be

• A. $2Kg\frac{m}{Sec}$
• B. $10Kg\frac{m}{Sec}$
• C. $12Kg\frac{m}{Sec}$
• D. $5\sqrt{2}Kg\frac{m}{sec}$

Answer 1

The correct option is D $5\sqrt{2}Kg\frac{m}{sec}$

Change in momentum $=$ Impulse

$\Delta \overrightarrow{P}=J_x\hat{i}+J_y\hat{j}+J_z\hat{k}$

$=30\left(0.1\right)\hat{i}+\frac{1}{2}\left(80\right)\left(0.1\right)\hat{j}+(-50)\times \left(0.1\right)\hat{k}$

$=3\hat{i}+4\hat{j}-5\hat{k}$

$\left|\Delta \overline{P}\right|=5\sqrt{2}kg\frac{m}{sec}$