wiz-icon
MyQuestionIcon
MyQuestionIcon
13
You visited us 13 times! Enjoying our articles? Unlock Full Access!
Question

A particle is an linear simple harmonic motion between two extreme point A and B. 10 cm apart(See figure below) If the direction from A to B is taken as positive direction, what are signs of displacement x, velocity V and acceleration a, when the particle is at A?

156096.jpg

A
x=ve,V=ve,a=ve
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x=+ve,V=0,a=ve
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x=+ve,V=ve,a=+ve
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x=ve,V=0,a=+ve
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D x=ve,V=0,a=+ve
When particle is at extreme A, velocity is zero. Since it is on the negative side of the mean, thus x is negative. Acceleration will be towards right that pulls it back (= - kx), thus acceleration is positive (as x is negative).

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Simple Harmonic Oscillation
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon