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Standard X

Physics

Natural Vibration

A particle is...

Question

A particle is describing SHM with amplitude $^{'} a^{'} .$ When the potential energy of particle is one fourth of the maximum energy during oscillation, then its displacement from mean position will be:

\frac{a}{4}

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\frac{a}{3}

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\frac{a}{2}

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\frac{2 a}{3}

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Solution

The correct option is C $\frac{a}{2}$

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A particle is describing SHM with amplitude ′a′. When the potential energy of particle is one fourth of the maximum energy during oscillation, then its displacement from mean position will be:

The correct option is C a2

A particle is describing SHM with amplitude $^{'} a^{'} .$ When the potential energy of particle is one fourth of the maximum energy during oscillation, then its displacement from mean position will be:

The correct option is C $\frac{a}{2}$