A particle is dropped from a tower 180 m high.How long does it take to reach the ground?What is the velocity when it touches the ground?
Take g= $10 m / s^{2}$ .

6 s, 60 m/s

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4.25 s, 42.5 m/s

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18 s, 180 m/s

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9 s, 90 m/s

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Solution

The correct option is A 6 s, 60 m/s
$s = u t + 0.5 a t^{2}$
$180 = 0 + 0.5 (10) t^{2}$
$t = 6 s$
$v = u + a t = 0 + 10 (6) = 60 m / s$

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