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Question

# A particle is dropped from the top of the tower of height H. Distance travelled by the particle in last second is 35 m. Find the height of the tower. [Take g=10 m/s2]

A
35 m
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B
45 m
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C
80 m
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D
60 m
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Solution

## The correct option is C 80 mGiven u=0,snth=35 m As we know that the distance travelled by a particle in nth sec is given as Snth=u+a2[2n−1] ⇒ −35=0−g2[2n−1] ⇒ 70=10[2n−1] ⇒ n=4 sec So, the total time of flight is n=t=4 sec Thus, height of tower is given as −H=−12gt2 ⇒ −H=−12×10×42 ⇒ H=80 m

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