Question

A particle is executing S.H.M. If its amplitude is 2 m and periodic time 2 seconds, then the maximum velocity of the particle will be

• A. m/s
• B. m/s
• C. 2 m/s
• D. 4 m/s

Answer 1

The correct option is C

2 m/s

$v_{max}=\omega a=\frac{2\pi }{T}\times a\Rightarrow v_{max}=\frac{2\times \pi \times 2}{2}=2\pi m/s$