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Question

A particle is executing simple harmonic motion with a period of T seconds and amplitude a meter. The shortest time it takes to reach a point a2m from its mean position in seconds is

A
T
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B
T/4
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C
T/8
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D
T/16
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Solution

The correct option is A T/8
The standard equation for SHM is denoted as:
y=sin2πTt

So, a2=asin2πT.t

So, the time taken to reach the point a2

2πT.t=12=sinπ4

2πTt=π4

t=T8

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