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A particle is executing simple harmonic motion with a time period T. At time t=0, it is at its position of equilibrium. The kinetic energy-time graph of the particle will look like


Solution

The correct option is A
Position of particle excecuting SHM.

x=Asinwt

Its velocity function is v=dxdt=Aωcoswt

Kinetic energy K.E. =12mv2=12mA2ω2cos2ωt

K.E.cos2ωt

But at t=T4,      cos(ωr4)=0K.E=0
 

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