Question

A particle is executing simple harmonic motion with an amplitude of 0.02 meter and frequency 50$Hz$ The maximum acceleration of the particle is

• A. 100$m/s^2$
• B. 100${\pi }^{2}m/s^2$
• C. 200$m/s^2$
• D. 200${\pi }^{2}m/s^2$

Answer 1

The correct option is D 200${\pi }^{2}m/s^2$

The maximum acceleration of the particle executing SHM is given as:

$A_{max}=4{\pi }^2{n}^{2}a$

$=4{\pi }^2\times (50{)}^2\times 0.02=200{\pi }^{2}m/s^2$