A particle is given an initial speed u inside a smooth spherical shell of radius R=1m, so that it is just able to complete the circle. Acceleration of the particle when its velocity is vertical, is
A
g√10
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B
g
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C
g√2
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D
3g
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Solution
The correct option is Ag√10 As per the question, the situation of the block is shown
As we know that the minimum velocity required to complete the circle is u2=5gR ∴ Applying the concept of energy conservation between A and B, we get v2=u2−2gR ⇒v2=5gR−2gR=3gR
Now, tangential acceleration at B is at=g (downwards) and, centripetal acceleration at B is ac=v2R=3gRR=3g ∴ Net acceleration at B will be an=√a2c+a2t=√(3g)2+(g)2=g√10