Question

A particle is in linear simple harmonic motion between two points $P$ and $Q$ represented by $x=A\text{sin}(\omega t+\varphi )$. Find the initial phase of the particle when it starts from its extreme position.

• A. $0$
• B. $\pi$
• C. $\frac{\pi }{2}$
• D. $2\pi$

Answer 1

The correct option is C $\frac{\pi }{2}$

Given,
$x=\text{A sin}(\omega t+\varphi )$
Since, the particle starts from extreme position
$A=\text{A sin}\left(\omega \right(0)+\varphi )$
$\Rightarrow \text{sin}\varphi =1$
$\Rightarrow \varphi =\frac{\pi }{2}$