Question

A particle is in S.H.M of amplitude $2$ cm. At extreme position the force is $4$N. At the point mid-way between mean and extreme position, the force is :

• A. $1$ N
• B. $2$N
• C. $3$N
• D. $4$N

Answer 1

The correct option is B $2$N

Amplitude = 2 cm
Force = 4N
$F=m{w}^{2}A=4$
$F_1=m{w}^{2}x$

Since $F$ is directly proportional to $x$ so , at midpoint the force when the amplitude is $2cm$ will be $2N$