A particle is moving along a circle and its linear velocity is 0.5ms−1 when its angular velocity is 2.5rads−1. Its tangential acceleration is 0.2ms−2 then its angular acceleration is:
A
1rads−2
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B
2rads−2
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C
2.5rads−2
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D
3rads−2
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Solution
The correct option is A1rads−2 a=αR=αvω⇒α=aωv=0.2×2.50.5=1rad/s2