Question

A particle is moving along a circle and its linear velocity is $0.5m{s}^{-1}$ when its angular velocity is $2.5rad{s}^{-1}$. Its tangential acceleration is $0.2m{s}^{-2}$ then its angular acceleration is:

• A. $1rad{s}^{-2}$
• B. $2rad{s}^{-2}$
• C. $2.5rad{s}^{-2}$
• D. $3rad{s}^{-2}$

Answer 1

The correct option is A $1rad{s}^{-2}$

$a=\alpha R=\alpha \frac{v}{\omega }\Rightarrow \alpha =\frac{a\omega }{v}=\frac{0.2\times 2.5}{0.5}=1rad/s^2$