Question

A particle is moving along a circle of radius $20/\pi$ with constant tangential acceleration. The velocity of the particle is 80m/s at the end of 2nd revolution after motion has began. Then the tangential acceleration is

Answer 1

$r=\frac{20}{\pi }$

In two revolution , distance is $s=2\times 2\pi r=80m$

Now, $v^2=2as$ for zero initial speed.

$⟹a=\frac{v^2}{2s}=\frac{80\times 80}{2\times 80}$

$⟹a=40m/s^2$