CameraIcon

SearchIcon

MyQuestionIcon

2

You visited us 2 times! Enjoying our articles? Unlock Full Access!

1st Equation of Motion

a particle is...

Question

a particle is moving along a circle such that its speed increases at a constant rate 0f 10m/s2 if radius of the circle is 10m and at an instant the speed of the particle is 20m/s then the angle between the velocity and the acceleration of the particle at that instant is 1. 1/tan(4) 2. 1/tan(2) 3. 1/tan(1/4) 4. 1/tan(1/2)

Open in App

Solution

Suggest Corrections

thumbs-up

8

Similar questions

Q. A particle is constrained to move in a circle with a 10-meter radius. At one instant, the particle's speed is 10 m/s and is increasing at a rate of

10 m / s^{2}

. The angle between the particle's velocity and acceleration vectors is.

Q. Find the angle between the net acceleration vector and tangential acceleration vector for a particle moving in a circle of radius

4 m

. If its speed is increasing at

3 m/s

every second, at an instant when the speed of the particle is

4 m/s

.

Q. A particle is revolving in a circular path having radius

‘ r^{'} = 1 m

2 m / s

. It is increasing its speed at the rate of

3 m / s^{2}

. The magnitude of total acceleration of the particle at that instant is

Q. A particle is moving on a circular path of 10 m radius. At any instant of time, its speed is 5

m s^{- 1}

and the speed is increasing at a rate of 2

m s^{- 1}

. The magnitude of net acceleration at this instant is then

Q. Find the angle between the net acceleration vector and tangential acceleration vector for a particle moving in a circle of radius

4 m

. If its speed is increasing at

3 m/s

every second, at an instant when the speed of the particle is

4 m/s

.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Motion Under Constant Acceleration

PHYSICS

Watch in App

explore_more_icon

Explore more

1st Equation of Motion

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon