Question

A particle is moving along a circular path of radius 5 m and with uniform speed 5 $m{s}^1$. What will be the average acceleration when the particle completes half revolution?

• A. $10\pi m{s}^{-2}$
• B. $10/\pi m{s}^{-2}$
• C. $10m{s}^{-2}$
• D. Zero

Answer 1

The correct option is B $10/\pi m{s}^{-2}$

Given that,

Radius $r=5m$

Speed $v=5m/s$

We know that,

The distance is the product of the velocity and time.

$d=v\times t$

So, the time is

$t=\frac{d}{v}$

Here, The distance is $\pi r$.

$t=\frac{\pi r}{v}$

$t=\frac{\pi \times 5}{5}$

$t=\pi sec$

The average acceleration will be

$a=\frac{totaldistance}{totaltime}$

$a=\frac{2r}{t}$

$a=\frac{10}{\pi }m/s^2$

The average acceleration will be $\frac{10}{\pi }m/s^2$

Hence, The correct option is B.