Question

A particle is moving along a circular path of radius $5m$ with a uniform speed $5m{s}^{-1}$. What is the magnitude of average acceleration during the interval in which particle completes half revolution?

Answer 1

$Time=\frac{2\pi \times 5}{5\times 2}=\frac{2\pi }{2}sec=\pi sec$
$AverageAcceleration=\frac{\Delta Velocity}{Time}=\frac{5-(-5)}{\pi }=\frac{10}{\pi }m/s^2$