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Question

A particle is moving along a circular path with a constant speed of 10 m/s. Find the magnitude of change in velocity of the particle when it moves through an angle of 60 around the centre of the circle.

A
102 m/s
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B
10 m/s
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C
103 m/s
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D
Zero
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Solution

The correct option is B 10 m/s
Figure shows the initial and final velocity of the particle, where particle has revolved around the circle through an angle 60


Change in velocity is given by, Δv=v2v1
Here, v2 and v1 represents the final and initial velocity respectively.
Δv=v21+v22+2v1v2cosθ ...(i)
Δv=102+1022×10×10×cos60
v1=v2=10 m/s
Δv=100=10 m/s
Magnitude of change in velocity is 10 m/s

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