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Question

A particle is moving along a circular path with a constant speed of 10 ms1. What is the magnitude of the change in velocity of the particle, when it moves through an angle of 60 around the centre of the circle?

A
102 m/s
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B
10 m/s
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C
103 m/s
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D
Zero
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Solution

The correct option is B 10 m/s

Change in velocity is given as:
Δv=v2v1=v2+(v1)

Here, θ=120 is the angle between the vectors v2 and v1 as represented in the figure.

Therefore, magnitude of change in velocity is given by:

Δv2=v21+v22+2v1v2cos120

v1=v2=v=10 m/s
Δv=v2+v2+2v×v×(12)
Δv=v=10 m/s

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