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Question

a particle is moving along x-axis has acceleration f at time t given by f=f'[1-(t/T)] , where f' and T are constant. the particle at t=0 has zero velocity. in the time interval between t=0 and the instant where f=0, the particle's velocity (v) is: (1) [1/2]f'T^2 (2) [1/2]f'T (3) f'T^2 (4) f'T

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Solution

99996266801-0-0

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