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v-t Graph

A particle is...

Question

A particle is moving in a circle of radius r having centre O, with constant speed v. What is the change in velocity in moving from A to B? $(∠ A O B = 40^{\circ})$

$2 V s i n 20^{\circ}$

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$4 V s i n 40^{\circ}$

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$2 V s i n 40^{\circ}$

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$V s i n 20^{\circ}$

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Solution

The correct option is A
$2 V s i n 20^{\circ}$

$Change in velocity = - \to V f - - \to V i Magnitude | V | = \sqrt{V^{2} + V^{2} - 2 V^{2} c o s 40^{\circ}} = 2 V s i n 20^{\circ}$

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A particle is moving in a circle of radius r having centre O, with constant speed v. What is the change in velocity in moving from A to B? (∠AOB=40∘)

The correct option is A 2Vsin20∘ Change in velocity=−→Vf−−→ViMagnitude |V|=√V2+V2−2V2 cos 40∘=2Vsin20∘

A particle is moving in a circle of radius r having centre O, with constant speed v. What is the change in velocity in moving from A to B? $(∠ A O B = 40^{\circ})$

The correct option is A
$2 V s i n 20^{\circ}$

$Change in velocity = - \to V f - - \to V i Magnitude | V | = \sqrt{V^{2} + V^{2} - 2 V^{2} c o s 40^{\circ}} = 2 V s i n 20^{\circ}$