Question

A particle is moving in a circle of radius $R$ with constant speed. The time period of the particle is $T$. In a time $t=\frac{T}{6}$, the magnitude of average velocity of the particle is

• A. $\frac{3R}{T}$
• B. $\frac{6R}{T}$
• C. $\frac{2R}{T}$
• D. $\frac{4R}{T}$

Answer 1

The correct option is B $\frac{6R}{T}$


$\text{Average velocity}=\frac{\text{chord PQ}}{\text{time}}$
Since $OP=OQ=R$, and all angles are equal, therefore $PQ=R$
$\text{Average velocity}=\frac{R}{T/6}=\frac{6R}{T}$