A particle is moving in a straight line and at some moment it occupied the positions (5,2) and (−1,−2). Then the position of the particle when it is on x−axis is
A
(−2,0)
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B
(0,2)
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C
(2,0)
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D
(4,0)
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Solution
The correct option is C(2,0) equation of the line
(y−2)=2−(−2)5−(−1)(x−5) (y−2)=46(x−5) y−2=23(x−5)
Now for y=0, it cuts x axes 0−2=23(x−5) −3=x−5 x=5−3=2
So, point is (2,0)