wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A particle is moving in a straight line with initial velocity u and uniform acceleration f. If the sum of the distances travelled in tth and (t+1)th seconds is 100 cm, then its velocity after t seconds (in cm/s) is

A
20
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
30
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
50
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
80
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 50
Sum of distance travelled in tth and (t+1)th second is 100 cm.
As we know that the distance travelled in tth second is given as,
st=u+a2(2t1)
100=st+st+1
100=u+f2(2t1)+u+f2[2(t+1)1]
100=2u+f2(2t1+2t+21)
100=2u+f2(4t)2u+2ft=100
50=u+ft
On comparing with first equation of motion, v=50 cm/s

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Motion Under Constant Acceleration
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon