Question

A particle is moving in a vertical circle, the tension in the string when passing through two position at angle ${30}^{\circ }$ and ${60}^{\circ }$ from vertical from lowest position are $T_1$ and $T_2$ respectively, then

• A. $T_1=T_2$
• B. $T_1>T_2$
• C. $T_1<T_2$
• D. $T_1\ge T_2$

Answer 1

The correct option is B $T_1>T_2$

In equilibrium, $T=m{v}^2/r+mg\cos \theta$
Since, $\theta$ increases $\cos \theta$ and $v$ both will decrease.
Hence, for $\theta ={60}^o$, the tension will be less.
Thus, $T_1>T_2$.