A particle is moving in a vertical circle- The tensions in the string when passing through two positions at angles 30- and 60- from vertical lowest position are T 1 and T 2 respectively- Then A- T1-T2B- T2-T1C- T1-T2D- Tension in the string always remains the same

The correct option is C T1 gt; T2Tension, T = mv^2/r + mg cos θ For, θ = 30^∘, T_1 = mv^2/r +mg cos 30^∘ θ = 60^∘, T_2 = mv^2/r + mg cos 60^∘ ∴ T_1 gt; ...

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Byju's Answer

Standard XII

Physics

Time Period of Pendulum

A particle is...

Question

A particle is moving in a vertical circle. The tensions in the string when passing through two positions at angles $30^{\circ}$ and $60^{\circ}$ from vertical (lowest position) are $T_{1}$ and $T_{2}$ respectively. Then

T₁ = T₂

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T₂ > T₁

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T₁ > T₂

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Tension in the string always remains the same

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Solution

The correct option is C T₁ > T₂
Tension, T = $\frac{m v^{2}}{r}$ + mg cos $θ$
For, $θ$ = $30^{\circ}$ , $T_{1}$ = $\frac{m v^{2}}{r}$ +mg cos $30^{\circ}$
$θ$ = $60^{\circ}$ , $T_{2}$ = $\frac{m v^{2}}{r}$ + mg cos $60^{\circ}$ $∴$ $T_{1}$ > $T_{2}$

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A particle is moving in a vertical circle. The tensions in the string when passing through two positions at angles 30∘ and 60∘ from vertical (lowest position) are T1 and T2 respectively. Then

The correct option is C T1 > T2Tension, T = mv2r + mg cos θ For, θ = 30∘, T1 = mv2r +mg cos 30∘ θ = 60∘, T2 = mv2r + mg cos 60∘ ∴ T1 > T2

A particle is moving in a vertical circle. The tensions in the string when passing through two positions at angles $30^{\circ}$ and $60^{\circ}$ from vertical (lowest position) are $T_{1}$ and $T_{2}$ respectively. Then

The correct option is C T₁ > T₂
Tension, T = $\frac{m v^{2}}{r}$ + mg cos $θ$
For, $θ$ = $30^{\circ}$ , $T_{1}$ = $\frac{m v^{2}}{r}$ +mg cos $30^{\circ}$
$θ$ = $60^{\circ}$ , $T_{2}$ = $\frac{m v^{2}}{r}$ + mg cos $60^{\circ}$ $∴$ $T_{1}$ > $T_{2}$