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Question

A particle is moving in conservative field. If work done by field to move particle from A to B is W1, from B to C is W2 and from C to A is W3, then


A
W1>W3+W2
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B
W2>W1+W3
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C
W1+W2+W3=0
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D
W1+W2+W3<0
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Solution

The correct option is C W1+W2+W3=0
Work done by conservative field is zero in a closed path.

Hence W1+W2+W3=0

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