Question

A particle is moving on a circle of radius 1 km with constant speed 10π m/s. Find the change in velocity vector of particle in a time duration of 1 second. (in m/s)

Answer 1

As we all know that change in velocity = Vfinal - Vinitial

As the motion is circular Initial velocity = -v

Then change in velocity = 2v
Acceleration = 2v/t
= 2v^2/(pi*r)

=
(2 x 100 xpi*pi)/(pi*1000)
= 22/35 m/s^2
A = change in velocity/time
22/35 = change in velocity