A particle is moving on x-axis has potential energy U=2−20x+5x2 joules along x-axis. The particle is released at x = – 3. If the mass of the particle is 0.1 kg and the maximum velocity of the particle (in m/s) is 10x, the value of x is
F=20−10x=–10(x−2)
Comparing with the data, we get amplitude=5
Hence, force constant is k = 10 ; m = 0.1 kg
Angular frequency, ω=√km=10 rad/s
vmax=wA=50 m/s