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Question

A particle is moving on x-axis has potential energy U=220x+5x2 joules along x-axis. The particle is released at x = – 3. If the mass of the particle is 0.1 kg and the maximum velocity of the particle (in m/s) is 10x, the value of x is ___ .

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Solution

F=2010x=10(x2)

Comparing with the data, we get amplitude=5

Hence, force constant is k = 10 ; m = 0.1 kg

Angular frequency, ω=km=10 rad/s

vmax=wA=50 m/s


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