Question

A particle is moving such that it's velocity varies as v^2 = 144+6x, x is the displacement of particle. Find the distance it travels in first 5 seconds

Answer 1

Dear Student

Given v²=144+6x
Comparing it with equation of motion v²=u²+2ax
We get u²=144 which give u=12
2ax=6x which gives a=3

Using it, v=u+at=12+(3*5)
v=27 m/s

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