Question

A particle is moving such that its position coordinates (x, y) are (2m, 3m) at time t = 0, (6m, 7m) at t = 2 sec and (13m, 14m) at time t = 5 sec. Average velocity vector $V_{avg}$ from t = 0 to t = 5 sec is:

• A. $\frac{13\hat{i}+14\hat{j}}{4}$
• B. $\frac{7}{3}(\hat{i}+\hat{j})$
• C. $\left(\widehat{i+\hat{j}}\right)$
• D. $\frac{11}{5}(\hat{i}+\hat{j})$

Answer 1

The correct option is D $\frac{11}{5}(\hat{i}+\hat{j})$

$S_1=2\hat{i}+3\hat{j}att=0S_2=6\hat{i}+7\hat{j}att=2sec{S}_3=13\hat{i}+14\hat{j}at=5secAveragevelocity=\frac{S_3-S_1}{t_{\left(5\right)}-t_{10}}=\frac{13\hat{i}+14\hat{j}-(2\hat{i}+3\hat{j})}{5-0}=\frac{11\hat{i}+11\hat{j}}{5}$