CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A particle is moving such that its position coordinates (x,y) are
(2m,3m) at time t=0,
(6m,7m) at time t=2 s and
(13m,14m) at time t=5 s.
Average velocity vector (Vav) from t=0 to t=5 s is:

A
15(13^i+14^j)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
73(^i+^j)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2(^i^j)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
115(^i+^j)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Join BYJU'S Learning Program
CrossIcon