A particle is moving uniformly in a circular path of radius 10m. When it moves through a displacement 5m, then the magnitude of the corresponding angular displacement will be:
A
20o
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B
30o
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C
600
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D
90o
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Solution
The correct option is C600 In the figure, the angle AOB is equal to θ.
The liner displacement corresponding to the angular displacement θ is AB.
We know AB = 5 m and r = 10 m
Let C be the mid point of AB. Hence the angle COB is θ/2. Since OBC forms a right angle triangle, BC=rsin(θ2)