Question

A particle is moving with a constant acceleration. Its velocity is reduced to zero in 5 s and it covered a distance of 100 m in this direction. The distance covered by the particle in the next 5s is

• A. Zero
• B. 250 m
• C. 100 m
• D. 500 m

Answer 1

The correct option is A Zero

A = (v - u)/t

= (0 - u)/t

= -u / (5 s)

S = ut + 0.5at²

100 = 5u + (0.5 × [-u / (5 s)] × (5 s)²)

100 = 5u - 2.5u

100 = 2.5u

u = 40 m/s

If u = 40 m/s then

a = -u / (5 s)

= -(40 m/s) / (5 s)

= -8 m/s²

Displacement covered in 10 seconds

S = ut + 0.5at²

= (40 m/s × 10 s) + [0.5 × (-8 m/s² × (10 s)²]

= 0 m

Particle travelled 100 m in first 5 seconds and in next 5 seconds it travels 100 m back to initial position. Hence we got Displacement after 10 seconds equal to zero.