A particle is moving with a uniform speed in a circular orbit of radius R in a central force inversely proportional to the nth power of R. If the period of rotation of the particle is T, then
A
T∝R(n+1)/2
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B
T∝Rn/2
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C
T∝R3/2 for any n
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D
T∝Rn2+1
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Solution
The correct option is AT∝R(n+1)/2 F=kRn=mω2R ω2∝1Rn+1⇒T=2πω
So, T∝Rn+12