Question

A particle is moving with a velocity of $v=(3+6t+9t^2)cm/s$. Find out the acceleration of the particle at $t=3/s$.

Answer 1

Velocity of the particle $v=(3+6t+9t^2)$ cm/s

$\therefore$ Acceleration of the particle $a=\frac{dv}{dt}=6+18t$ $cm/s^2$

Acceleration at $t=3$ s, $a{|}_{t=3}=6+18\left(3\right)=60$ $cm/s^2$