Question

A particle is moving with centripetal force $\frac{k}{r^2}$. Find the total energy associated.

Answer 1

$\frac{m{v}^2}{r}=\frac{k}{r^2}$ or $m{v}^2=\frac{k}{r}$
Total energy $=KE+PE=-KE=-\frac{k}{2r}$