Question

A particle is moving with constant acceleration $a$. The following graph shows $v^2$ versus $x$(displacement) plot. The acceleration of the particle is
${\text{ms}}^{-1}$

Answer 1

Slope of the graph is,

$\frac{d\left(v^2\right)}{dx}=\frac{vdv}{dx}$,

which is acceleration of the particle.

Two point formula for slope of the straight line is, $\frac{y_2-y_1}{x_2-x_1}$

Here $(x_1,y_1)=(10,40)(x_2,y_2)=(20,60)$

Hence, $a=\frac{60-40}{20-10}=2{\text{ms}}^{-2}$

Correct answer: $2$