Question

A particle is performing a linear simple harmonic motion. If the acceleration and the corresponding velocity of the particle are a and v respectively, then which of the following graphs is correct?

• A.
• B.
• C.
• D.

Answer 1

The correct option is C

$v=-A\omega \sin \omega t$
$a=-A{\omega }^2\cos \omega t$
$\therefore {\left(\frac{-v}{A\omega }\right)}^2+{\left(\frac{a}{A{\omega }^2}\right)}^2=1$
It represents an ellipse