2
You visited us
2
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Physics
Angular Velocity
a particle is...
Question
a particle is performing circular motion in a circle of radius R with variable speed,v=Kt (k>0).time when angle between acceleration vector and its velocity vector becomes pi/4,is 4 root (R/nk).the value of n is
Open in App
Solution
Suggest Corrections
4
Similar questions
Q.
Find the angle between the net acceleration vector and tangential acceleration vector for a particle moving in a circle of radius
4
m
with its speed increasing at
3
m
/
s
every second, when the speed of the particle is
4
m
/
s
.
Q.
Find the angle between the net acceleration vector and tangential acceleration vector for a particle moving in a circle of radius
4
m
with its speed increasing at
3
m
/
s
every second, when the speed of the particle is
4
m
/
s
.
Q.
Find the angle between the net acceleration vector and tangential acceleration vector for a particle moving in a circle of radius
4
m
. If its speed is increasing at
3
m/s
every second, at an instant when the speed of the particle is
4
m/s
.
Q.
A particle starts from rest, travelling on a circle with constant tangential acceleration. The angle between velocity vector and acceleration vector, at the moment when the particle completes half the circular track is
Q.
The velocity and acceleration vectors of a particle undergoing circular motion are
→
v
=
2
^
i
m
/
s
and
→
a
=
2
^
i
+
4
^
j
m
/
s
2
respectively at an instant of time. The radius of the circle is
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Relative
PHYSICS
Watch in App
Explore more
Angular Velocity
Standard XII Physics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app