Question

A particle is performing SHM of amplitude "A" and time period "T". Find the time taken by the particle to go from 0 to A /$\sqrt{2}$.

• A. T/12
• B. T/$\sqrt{2}$
• C. T/6
• D. t/4

Answer 1

The correct option is A T/12

Let equation of SHM be x = A $\sin \omega t$
when x = 0 t = 0 when x = A/2 ; A/2 = A $\sin \omega t$
or $\sin \omega t=1/2$ $\omega t=\pi /6$
$\frac{2\pi }{T}t=\pi /6$ t=T/12
Hence time taken is T/12 where T is time period of SHM