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Question

A particle is projected along an inclined plane as shown in figure. What is the speed of the particle when it collides at point A? (g=10m/s2)
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Solution

Given : u=10 m/s
Initial velocity along x direction ux=ucos30o m/s
Initial velocity along y direction uy=usin30o m/s
Also acceleration x and y direction ax=gsin30o m/s2 and ay=gcos30o m/s2

x direction : Vx=ux+axt
time t=2×10sin3010cos30, hence t=23 s
Vx=ucos30o(gsin30o)t

OR Vx=10×3210×0.5×23 = 15103=53 m/s
Also Vy=5 m/s (solved earlier)
Speed of the particle at collision V=V2x+V2y=(53)2+(5)2

V=1003=103 m/s

517591_244271_ans.png

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