Question

A particle is projected at an angle of ${30}^0$ with the horizontal with a momentum $P$. At the highest point its momentum is

• A. $\frac{\sqrt{3}}{2}P$
• B. $\frac{2}{\sqrt{3}}P$
• C. $P$
• D. $\frac{1}{2}P$

Answer 1

The correct option is A $\frac{\sqrt{3}}{2}P$

At the point of projection, $P=mu$

At the highest point, vertical component of velocity is 0.

Therefore, $u_x=ucos{30}^0$

$P^{\prime }=m\left(u\cos \theta \right)$

$=mu\frac{\sqrt{3}}{2}$

$=\frac{P\sqrt{3}}{2}$