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Question

A particle is projected at an angle of 37 with an inclined plane as shown in figure. Calculate:

(i) Time of flight of particle.

(ii) Distance traveled by particle (AB) along the inclined plane


A

Time of flight = 125sec

Distance along incline = 125(863)m

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B

Time of flight = 2 sec

Distance along incline = 16 m

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C

Time of flight = 3 sec

Distance along incline = 6 m

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D

Time of flight = 125sec

Distance along incline = (863)m

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Solution

The correct option is A

Time of flight = 125sec

Distance along incline = 125(863)m


(i) To find out time of flight here, we can analyze the motion in y-direction; we can use the formula y=uyt+12ayt2. By analyzing motion in y-direction , the displacement of the particle in y-direction during motion is zero.

Now uy=usin α=u.sin 37=35×10=6 ms

ay=gcos θ=gcos 60=10×12=5 ms2

So, y=uyt+12ayt20=6t52t2t=125s

(ii) To find out the distance traveled along AB, we have to analyze the motion in x-direction. So we have to use the formula

x=uxt+12axt2

Here ux=ucos α=10cos 37=10×45=8 msax=gsin θ=10sin 60=10×32=53 ms2

And t=125s, x=8×12512.53(125)2=965532×14425=9657235=125(863)m


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