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Question

A particle is projected at an angle with the horizontal such that it follows a trajectory given by the equation y=6x2x2. Find the maximum height attained by it.

A
2.5 m
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B
5.2 m
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C
4.5 m
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D
6 m
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Solution

The correct option is C 4.5 m
Trajectory of a projectile is given by the eqn
y=xtanθ(1xR)
If y=axbx2, then tanθ=a
and b=tanθRR=ab
For maximum height H, we have
maximum height, H=u2sin2θ2g and Range R=u2sin2θg
So, we have the ratio HR=u2sin2θ2gu2sin2θg
4HR=tanθSince, y=6x2x2H=14Rtanθ=a24b=624×2=4.5 m

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