Question

A particle is projected at angle ${37}^o$ with the incline plane in upward direction with speed $10$m/s. The angle of incline plane is given ${53}^o$. Then the maximum height attained by the particle from the incline plane will be:

• A. $3m$
• B. $4m$
• C. $5m$
• D. zero

Answer 1

The correct option is C $5m$

From the fig. $37°+53°=90°$

The particle is projected straight upwards,maximum height is obtained.

$H=\frac{u^2{\sin }^2\theta }{2g}=\frac{u^2{\sin }^2{90}^{\circ }}{2g}$

$=\frac{100}{2\times 10}=5m$