A particle is projected at angle θ with horizontal, with velocity v0 at t=0. Find the radius of curvature at t=0.
A
v20/gcosθ
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B
v20cosθ/g
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C
(v0cosθ)2/g
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D
v20/g
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Solution
The correct option is Av20/gcosθ
The net acceleration of the particle during the motion is g.
Normal acceleration (centripetal acceleration) at t=0,an=gcosθ
Let the radius of curvature at t=0 be R0.
Then, an=v2R=v20R0 ⇒R0=v20an=v20gcosθ